3f^2+7f-7=0

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Solution for 3f^2+7f-7=0 equation: 



3f^2+7f-7=0

a = 3; b = 7; c = -7;
Δ = b2-4ac
Δ = 72-4·3·(-7)
Δ = 133
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{133}}{2*3}=\frac{-7-\sqrt{133}}{6}
$


$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{133}}{2*3}=\frac{-7+\sqrt{133}}{6}
$

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